Pump hydraulic power

A compact explanation of hydraulic power, flow conversion and efficiency for preliminary water-pump sizing.

ENGINEERING PRINCIPLE

Hydraulic power is the rate at which a pump increases fluid potential energy; shaft input rises as efficiency falls.

Pinput = ρgQH/η
Fluid MechanicsSource reference providedSource record dated 2026-08-09

Variables and units

  • ρ in kg/m³
  • g in m/s²
  • Q in m³/s
  • H in m
  • η as a decimal

Worked example

For water at Q = 0.015 m³/s, H = 30 m and η = 0.70, Pinput = 1000 × 9.81 × 0.015 × 30 / 0.70 = 6.31 kW.

Calculation method

  1. Convert flow to m³/s.
  2. Use a fluid density at the actual process temperature and pressure.
  3. Divide hydraulic power by an efficiency appropriate to the planned operating point.

Practical applications

  • Water-transfer systems
  • Process circulation loops
  • Initial motor-capacity estimates

Review boundary and reference

  • Pump selection needs a system curve and manufacturer curve.
  • NPSH, viscosity, motor efficiency and transient duty must be checked separately.

Formula and displayed units independently checked for the stated conditions. This is not a code-compliance design method.

Source: Hydraulic-power relation derived from conservation of energy; use manufacturer curves for selection.

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