Stress, strain and elastic modulus

The distinction between load intensity, deformation and stiffness in a small-strain elastic material model.

ENGINEERING PRINCIPLE

Within a linear elastic range, normal stress is proportional to normal strain and the proportionality is Young’s modulus.

σ = F/A; ε = ΔL/L₀; E = σ/ε
Strength of MaterialsVerifiedReviewed 2026-08-09

Variables and units

  • σ = normal stress (MPa)
  • ε = normal strain (mm/mm)
  • E = Young’s modulus (GPa)

Worked example

A 20 kN axial load on 500 mm² gives 40 MPa. If a 100 mm gauge length elongates by 0.02 mm, ε = 0.0002 and E = 200 GPa.

Calculation method

  1. Use the original loaded area for nominal engineering stress.
  2. Use the original gauge length for engineering strain.
  3. Only divide stress by strain in the verified linear elastic range.

Practical applications

  • Tie rods and specimens
  • Material comparison
  • Elastic deflection estimates

Review boundary and reference

  • Stress concentrations, plasticity and temperature change invalidate a simple uniform model.
  • Use certified material properties for critical work.

Formula and displayed units independently checked for the stated conditions. This is not a code-compliance design method.

Source: Standard mechanics-of-materials treatment of uniaxial elastic response; NIST SP 811 for units.

Related calculators

Open calculator →Open calculator →Open calculator →
Stress, strain and elastic modulus | AIEngineeringTool